PHP JSON~ json_decode

由於我存資料庫是存json到一個欄位.........現在的問題是...

要輸出excel檔~~~@0@

意思就是~~~我要在PHP底下把JSON解譯出來~~json_decode()

$rr = '{"yyy":"321", "zzz":"123", "xxx": {"a":"1", "b":"2"} }';

$yy = json_decode($rr);

print_r($yy);

Output:

stdClass Object
(
    [yyy] => 321
    [zzz] => 123
    [xxx] => stdClass Object
        (
            [a] => 1
            [b] => 2
        )
)

可以看出$yy已經從JSON字串變成物件了

如果要取xxx裡面的a的值

print $yy->xxx->a;

http://www.php.net/manual/en/function.json-decode.php